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if det(A)=0 , then AB is singular
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Prove the following:
1- if det(A)=0 , then AB is singular .
2- if A and B are invertible then AB is invertible . with (AB)^-1 = B^-1 A^-1
3- if A is invertible and B , C are inverses of A , the B=C .
4- if A is invertible then det (A^-1)= 1/det (A) .

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